I've always been bothered with normal operator ordering, writing $:O(a)O(b):$ always produces bad results.
The quick fix I've been using is the following:
\def\normOrd#1{\mathop{:}\nolimits\!#1\!\mathop{:}\nolimits}
%%
% example:
% \begin{equation}
% \normOrd{a(z)b(\omega)} = a(z)_{+}b(\omega)+(-1)^{\alpha\beta}b(\omega)a(z)_{-}
% \end{equation}
%%
Which in practice looks like:How I got this solution
I determined this solution iteratively after many different attempts, which I shall enumerate along with the problems they each had.However, using mere colons
:a(z)b(\omega): = ... produces the following:Being clever, I asked myself "Hey, why not write
:x\colon for the normal ordering?" This was clever, but wrong. Consider the following example:g = :x\colonProducing:
Not one to give up easily, I found a
\cocolon definition on tex.stackexchange. Trying that instead:g = \cocolon x\colon = yProduces strange extra whitespace on the right:
After examining the co-colon code, I just determined that something along the lines of
% rough draft definition #1
\def\normOrd#1{\mathrel{:}\!#1\!\mathrel{:}}
would work. This didn't quite work, the whitespacing was strange. So instead I just use \mathop{:}\nolimits..., which produces the desired result.