I've always been bothered with normal operator ordering, writing $:O(a)O(b):$
always produces bad results.
The quick fix I've been using is the following:
\def\normOrd#1{\mathop{:}\nolimits\!#1\!\mathop{:}\nolimits} %% % example: % \begin{equation} % \normOrd{a(z)b(\omega)} = a(z)_{+}b(\omega)+(-1)^{\alpha\beta}b(\omega)a(z)_{-} % \end{equation} %%Which in practice looks like:
How I got this solution
I determined this solution iteratively after many different attempts, which I shall enumerate along with the problems they each had.However, using mere colons
:a(z)b(\omega): = ...
produces the following:Being clever, I asked myself "Hey, why not write
:x\colon
for the normal ordering?" This was clever, but wrong. Consider the following example:g = :x\colonProducing:
Not one to give up easily, I found a
\cocolon
definition on tex.stackexchange. Trying that instead:g = \cocolon x\colon = yProduces strange extra whitespace on the right:
After examining the co-colon code, I just determined that something along the lines of
% rough draft definition #1 \def\normOrd#1{\mathrel{:}\!#1\!\mathrel{:}}would work. This didn't quite work, the whitespacing was strange. So instead I just use
\mathop{:}\nolimits...
, which produces the desired result.